6. Найди значение суммы или разности. А) \(\frac{1}{3}+\frac{1}{6}\); \(\frac{1}{2}+\frac{1}{3}\); \(\frac{3}{5}-\frac{1}{10}\); \(\frac{1}{12}+\frac{5}{6}\); \(\frac{1}{3}+\frac{1}{4}\). Б) \(\frac{1}{3}-\frac{1}{6}\); \(\frac{3}{20}+\frac{3}{4}\); \(\frac{7}{9}-\frac{2}{3}\); \(\frac{1}{4}+\frac{1}{5}\); \(\frac{2}{5}+\frac{4}{15}\). В) \(\frac{11}{20}-\frac{5}{12}\); \(\frac{8}{9}+\frac{7}{54}\); \(\frac{5}{6}-\frac{17}{21}\); \(\frac{3}{16}+\frac{1}{24}\); \(\frac{5}{6}-\frac{22}{27}\).

Приведём дроби к общему знаменателю и выполним действие.

А:

1. \(\frac{1}{3}+\frac{1}{6}=\frac{2}{6}+\frac{1}{6}=\frac{3}{6}=\frac{1}{2}\).
2. \(\frac{1}{2}+\frac{1}{3}=\frac{3}{6}+\frac{2}{6}=\frac{5}{6}\).
3. \(\frac{3}{5}-\frac{1}{10}=\frac{6}{10}-\frac{1}{10}=\frac{5}{10}=\frac{1}{2}\).
4. \(\frac{1}{12}+\frac{5}{6}=\frac{1}{12}+\frac{10}{12}=\frac{11}{12}\).
5. \(\frac{1}{3}+\frac{1}{4}=\frac{4}{12}+\frac{3}{12}=\frac{7}{12}\).

Б:

1. \(\frac{1}{3}-\frac{1}{6}=\frac{2}{6}-\frac{1}{6}=\frac{1}{6}\).
2. \(\frac{3}{20}+\frac{3}{4}=\frac{3}{20}+\frac{15}{20}=\frac{18}{20}=\frac{9}{10}\).
3. \(\frac{7}{9}-\frac{2}{3}=\frac{7}{9}-\frac{6}{9}=\frac{1}{9}\).
4. \(\frac{1}{4}+\frac{1}{5}=\frac{5}{20}+\frac{4}{20}=\frac{9}{20}\).
5. \(\frac{2}{5}+\frac{4}{15}=\frac{6}{15}+\frac{4}{15}=\frac{10}{15}=\frac{2}{3}\).

В:

1. \(\frac{11}{20}-\frac{5}{12}=\frac{33}{60}-\frac{25}{60}=\frac{8}{60}=\frac{2}{15}\).
2. \(\frac{8}{9}+\frac{7}{54}=\frac{48}{54}+\frac{7}{54}=\frac{55}{54}=1\frac{1}{54}\).
3. \(\frac{5}{6}-\frac{17}{21}=\frac{35}{42}-\frac{34}{42}=\frac{1}{42}\).
4. \(\frac{3}{16}+\frac{1}{24}=\frac{9}{48}+\frac{2}{48}=\frac{11}{48}\).
5. \(\frac{5}{6}-\frac{22}{27}=\frac{45}{54}-\frac{44}{54}=\frac{1}{54}\).

Ответ: А) \(\frac{1}{2};\ \frac{5}{6};\ \frac{1}{2};\ \frac{11}{12};\ \frac{7}{12}\). Б) \(\frac{1}{6};\ \frac{9}{10};\ \frac{1}{9};\ \frac{9}{20};\ \frac{2}{3}\). В) \(\frac{2}{15};\ 1\frac{1}{54};\ \frac{1}{42};\ \frac{11}{48};\ \frac{1}{54}\).