Ответ:

\(2\frac15−\left(2−1\frac1{15}\right)+\frac49+\frac23\)

\(=\frac{11}{5}−\frac{14}{15}+\frac49+\frac23\)

\(=\frac{99}{45}−\frac{42}{45}+\frac{20}{45}+\frac{30}{45}=\frac{107}{45}=2\frac{17}{45}\).

Ответ: \(2\frac{17}{45}\).