- \(\sqrt2\cdot\sqrt8=\sqrt{16}=4\).
- \(\sqrt6\cdot\sqrt{54}=\sqrt{324}=18\).
- \(\dfrac{\sqrt{50}}{\sqrt2}=\sqrt{25}=5\).
- \(\dfrac{\sqrt{72}}{\sqrt8}=\sqrt9=3\).
- \(\dfrac{\sqrt{12}\cdot\sqrt{15}}{\sqrt5}=\sqrt{\dfrac{12\cdot15}{5}}=\sqrt{36}=6\).
- \(\sqrt8\cdot\sqrt6\cdot\sqrt{12}=\sqrt{8\cdot6\cdot12}=\sqrt{576}=24\).
- \(\sqrt{15}\cdot\sqrt3\cdot\sqrt{20}=\sqrt{900}=30\).
- \(\dfrac{\sqrt{28}\cdot\sqrt{49}}{\sqrt7}=\sqrt{\dfrac{28\cdot49}{7}}=\sqrt{196}=14\).
- \(\sqrt{18}\cdot\sqrt{50}-\dfrac{\sqrt{3456}}{\sqrt6}=\sqrt{900}-\sqrt{576}=30-24=6\).
Ответ: а) 4; б) 18; в) 5; г) 3; д) 6; е) 24; ж) 30; з) 14; и) 6.