Ответ:

1а)

Сначала вычислим выражение в скобках:

\(12\frac{1}{3}:5=\frac{37}{3}:5=\frac{37}{15}\), \(\frac{1}{6}\cdot3=\frac{1}{2}\).

\(\frac{37}{15}-\frac{1}{2}=\frac{74-15}{30}=\frac{59}{30}\).

Тогда \(1\frac{1}{3}\cdot\frac{59}{30}=\frac{4}{3}\cdot\frac{59}{30}=\frac{118}{45}\).

\(5\frac{1}{3}-\frac{118}{45}=\frac{16}{3}-\frac{118}{45}=\frac{240-118}{45}=\frac{122}{45}=2\frac{32}{45}\).

1б)

\(7\frac{1}{5}:6=\frac{36}{5}:6=\frac{6}{5}\), \(\frac{1}{10}\cdot2=\frac{1}{5}\).

\(\frac{6}{5}-\frac{1}{5}=1\).

\(2\frac{2}{3}\cdot1=2\frac{2}{3}\).

\(2\frac{1}{3}+2\frac{2}{3}=5\).

2а)

\(0,8:0,16=5\), \(0,16\cdot0,5=0,08\).

\(5-0,08=4,92\).

\(1,5\cdot4,92=7,38\).

\(8,5+7,38=15,88\).

2б)

\(0,9:0,18=5\), \(0,18\cdot0,5=0,09\).

\(5-0,09=4,91\).

\(2,5\cdot4,91=12,275\).

\(12,5-12,275=0,225\).

Ответ: 1а) \(2\frac{32}{45}\); 1б) \(5\); 2а) \(15,88\); 2б) \(0,225\).