Ответ:

Смешанные числа переводим в неправильные дроби, затем перемножаем и сокращаем.

  1. а) \(1\frac{3}{7}\cdot1\frac{1}{4}=\frac{10}{7}\cdot\frac{5}{4}=\frac{25}{14}=1\frac{11}{14}\).
  2. б) \(3\frac{1}{5}\cdot\frac{3}{8}=\frac{16}{5}\cdot\frac{3}{8}=\frac{6}{5}=1\frac{1}{5}\).
  3. в) \(9\cdot1\frac{4}{6}=9\cdot\frac{5}{3}=15\).
  4. г) \(3\frac{17}{21}\cdot3\frac{1}{8}=\frac{80}{21}\cdot\frac{25}{8}=\frac{250}{21}=11\frac{19}{21}\).
  5. д) \(16\frac{2}{3}\cdot\frac{1}{5}=\frac{50}{3}\cdot\frac{1}{5}=\frac{10}{3}=3\frac{1}{3}\); \(2\frac{3}{4}\cdot3\frac{1}{3}=\frac{11}{4}\cdot\frac{10}{3}=\frac{55}{6}=9\frac{1}{6}\).
  6. е) \(5\frac{2}{5}\cdot3\frac{1}{3}=\frac{27}{5}\cdot\frac{10}{3}=18\); \(3\frac{1}{3}\cdot\frac{3}{5}=\frac{10}{3}\cdot\frac{3}{5}=2\).
  7. ж) \(1\frac{2}{7}\cdot1\frac{1}{4}=\frac{9}{7}\cdot\frac{5}{4}=\frac{45}{28}=1\frac{17}{28}\); \(6\frac{1}{2}\cdot1\frac{1}{39}=\frac{13}{2}\cdot\frac{40}{39}=\frac{20}{3}=6\frac{2}{3}\).
  8. з) \(33\frac{1}{3}\cdot1\frac{1}{5}=\frac{100}{3}\cdot\frac{6}{5}=40\); \(2\frac{4}{5}\cdot6\frac{3}{7}=\frac{14}{5}\cdot\frac{45}{7}=18\).
  9. и) \(2\frac{2}{5}\cdot13\frac{1}{3}=\frac{12}{5}\cdot\frac{40}{3}=32\); \(3\frac{1}{16}\cdot1\frac{5}{7}=\frac{49}{16}\cdot\frac{12}{7}=\frac{21}{4}=5\frac{1}{4}\).

Ответ: а) \(1\frac{11}{14}\); б) \(1\frac{1}{5}\); в) 15; г) \(11\frac{19}{21}\); д) \(3\frac{1}{3}\), \(9\frac{1}{6}\); е) 18, 2; ж) \(1\frac{17}{28}\), \(6\frac{2}{3}\); з) 40, 18; и) 32, \(5\frac{1}{4}\).