Решение:
- \(17a - 13a = 4a\)
- \(\frac{7a}{14b} = \frac{a}{2b}\)
- \((11a \cdot 2) \cdot 0.1 = 22a \cdot 0.1 = 2.2a\)
- \((9a \cdot 8) : 3.6 = 72a : 3.6 = 20a\)
- \(\frac{a \cdot 3}{18} = \frac{3a}{18} = \frac{a}{6}\)
- \(\frac{4}{9}a \cdot \frac{3}{8}b = \frac{4 \cdot 3}{9 \cdot 8}ab = \frac{12}{72}ab = \frac{1}{6}ab\)
- \(12a + 10a - 9a = 22a - 9a = 13a\)
- \(15a \cdot 4 = 60a\)
- \(16a : 0.4 = \frac{16a}{0.4} = 40a\)
- \((7a \cdot 4) : \frac{1}{2} = 28a \cdot 2 = 56a\)
- \(14a : 7 = 2a\)
- \((7.6 \cdot a) : \frac{7}{5} = \frac{7.6a}{7/5} = \frac{7.6a \cdot 5}{7} = \frac{38a}{7} \)
- \(\frac{a \cdot 5}{25} = \frac{5a}{25} = \frac{a}{5}\)
- \((2.3a) : 0.01 = \frac{2.3a}{0.01} = 230a\)
- \((1.3 \cdot a) : 0.1 = \frac{1.3a}{0.1} = 13a\)
Ответ: 4a, \(\frac{a}{2b}\), 2.2a, 20a, \(\frac{a}{6}\), \(\frac{1}{6}ab\), 13a, 60a, 40a, 56a, 2a, \(\frac{38a}{7}\), \(\frac{a}{5}\), 230a, 13a.