649. Есептеңдер: 1) $(2\frac{1}{3})^2-\frac{4}{9}$; 2) $(1\frac{1}{2})^3+\frac{5}{8}$; 3) $3\frac{5}{9}+(\frac{2}{3})^2$; 4) $(\frac{1}{2})^4+3\frac{1}{4}$; 5) $7\frac{2}{5}-(\frac{2}{5})^2$; 6) $9-(1\frac{1}{3})^2$.

Question

Вопрос: $Фото задания: 649. Есептеңдер: 1) $(2\frac{1}{3})^2-\frac{4}{9}$; 2) $(1\frac{1}{2})^3+\frac{5}{8}$; 3)…$ Фото задания

Accepted Answer

$(\frac{7}{3})^2-\frac{4}{9}=\frac{49}{9}-\frac{4}{9}=5$.
$(\frac{3}{2})^3+\frac{5}{8}=\frac{27}{8}+\frac{5}{8}=4$.
$3\frac{5}{9}+(\frac{2}{3})^2=\frac{32}{9}+\frac{4}{9}=4$.
$(\frac{1}{2})^4+3\frac{1}{4}=\frac{1}{16}+\frac{13}{4}=\frac{53}{16}=3\frac{5}{16}$.
$7\frac{2}{5}-(\frac{2}{5})^2=\frac{37}{5}-\frac{4}{25}=\frac{181}{25}=7\frac{6}{25}$.
$9-(1\frac{1}{3})^2=9-(\frac{4}{3})^2=\frac{81}{9}-\frac{16}{9}=\frac{65}{9}=7\frac{2}{9}$.

Жауап: 1) 5; 2) 4; 3) 4; 4) $3\frac{5}{16}$; 5) $7\frac{6}{25}$; 6) $7\frac{2}{9}$.

649. Есептеңдер: 1) \((2\frac{1}{3})^2-\frac{4}{9}\); 2) \((1\frac{1}{2})^3+\frac{5}{8}\); 3) \(3\frac{5}{9}+(\frac{2}{3})^2\); 4) \((\frac{1}{2})^4+3\frac{1}{4}\); 5) \(7\frac{2}{5}-(\frac{2}{5})^2\); 6) \(9-(1\frac{1}{3})^2\).