Ответ:
а) \(0.7b+0.3(b-5)=0.7\cdot(-0.81)+0.3\cdot(-5.81)=-0.567-1.743=-2.31\).
б) \(1.7(a-11)-16.3=1.7\cdot(3.8-11)-16.3=1.7\cdot(-7.2)-16.3=-12.24-16.3=-28.54\).
в) \(x=4\frac{1}{6}=\frac{25}{6}\):
\(0.6(4x-14)-0.4(5x-1)=0.6\left(\frac{100}{6}-14\right)-0.4\left(\frac{125}{6}-1\right)\)
\(=0.6\cdot\frac{8}{3}-0.4\cdot\frac{119}{6}=\frac{8}{5}-\frac{119}{15}=-\frac{19}{3}\).
г) \(5\frac{1}{7}=\frac{36}{7}\), \(4\frac{4}{7}=\frac{32}{7}\), поэтому
\(\frac{36}{7}(-0.3-7)-\frac{32}{7}(14+0.3)\)
\(=\frac{36}{7}\cdot\left(-\frac{73}{10}\right)-\frac{32}{7}\cdot\frac{143}{10}=\frac{974}{35}=27\frac{29}{35}\).
Ответ: а) −2,31; б) −28,54; в) \(-\frac{19}{3}\); г) \(27\frac{29}{35}\).
