7) P = 18 QLP Q /| x | x / | L---P Ответ:

The image displays a geometry problem labeled '7) P_QLP = 18'. It shows a circle with points Q and P on its circumference. There is an external point L. Line segments LQ and LP are drawn, and a segment QP is a chord of the circle. The lengths LQ and LP are marked with 'x', indicating they are equal. The segment QP is also marked with two small tick marks, and the segment LQ is also marked with two small tick marks, suggesting a relationship between lengths. However, the segment QP is labeled with 'x'. This creates an ambiguity. Let's assume the 'x' next to QP represents its length. If LQ = LP = x, and QP = x, then triangle QLP is an equilateral triangle. The perimeter of triangle QLP is given as 18. The perimeter is the sum of the lengths of its sides: P_QLP = LQ + LP + QP. If LQ = LP = QP = x, then the perimeter is x + x + x = 3x. We are given that the perimeter is 18. So, 3x = 18. Solving for x: x = 18 / 3 = 6. Therefore, x = 6. However, let's re-examine the diagram. The segment QP has a length labeled 'x'. The segments LQ and LP are also labeled with 'x'. This implies that LQ = LP = QP = x. If this is the case, then triangle QLP is equilateral. The perimeter of triangle QLP is the sum of its side lengths: LQ + LP + QP. We are given that P_QLP = 18. So, x + x + x = 18. This simplifies to 3x = 18. Dividing by 3, we get x = 6. Let's consider another interpretation of the markings. The tick marks on LQ and LP suggest that LQ = LP. The tick marks on QP are not explicitly stated to be equal to LQ and LP. However, the label 'x' is placed next to the segment QP, implying its length is x. Thus, LQ = x, LP = x, and QP = x. This leads to an equilateral triangle QLP. The perimeter is given as 18. Therefore, the sum of the sides is x + x + x = 3x = 18. Solving for x, we get x = 18 / 3 = 6. Final check: If x = 6, then LQ = 6, LP = 6, and QP = 6. The perimeter is 6 + 6 + 6 = 18, which matches the given information. Therefore, x = 6.