7) Simplify the expression \( \frac{x^3 - 3x^2 - 2x + 6}{x^3 - 27} \).

\( \frac{x^3 - 3x^2 - 2x + 6}{x^3 - 27} = \frac{(x - 3)(x^2 - 2)}{(x - 3)(x^2 + 3x + 9)} = \frac{x^2 - 2}{x^2 + 3x + 9} \) (assuming \( x
eq 3 \)).