8) $\frac{9}{12}+\frac{16}{20}-\frac{9}{10}$ и $\frac{3}{6}-\frac{2}{8}+\frac{6}{12}$

Question

Вопрос: $Фото задания: 8) $\frac{9}{12}+\frac{16}{20}-\frac{9}{10}$ и $\frac{3}{6}-\frac{2}{8}+\frac{6}{12}$$ Фото задания

Accepted Answer

$\frac{9}{12}+\frac{16}{20}-\frac{9}{10}=\frac{15}{20}+\frac{16}{20}-\frac{18}{20}=\frac{13}{20}=0{,}65$.

$\frac{3}{6}-\frac{2}{8}+\frac{6}{12}=\frac{1}{2}-\frac{1}{4}+\frac{1}{2}=\frac{3}{4}=0{,}75$.

Ответ: $0{,}65$ и $0{,}75$.

8) \(\frac{9}{12}+\frac{16}{20}-\frac{9}{10}\) и \(\frac{3}{6}-\frac{2}{8}+\frac{6}{12}\)