855. Решите неравенство:

a) (2a-1)/2 - (3a-3)/5 > a => (5(2a-1) - 2(3a-3))/10 > a => 10a - 5 - 6a + 6 > 10a => 4a + 1 > 10a => 1 > 6a => a < 1/6.

б) x - (2x+3)/2 <= (x-1)/4 => (4x - 2(2x+3))/4 <= (x-1)/4 => 4x - 4x - 6 <= x - 1 => -6 <= x - 1 => -5 <= x.

в) (5x-1)/5 + (x+1)/2 <= x => (2(5x-1) + 5(x+1))/10 <= x => 10x - 2 + 5x + 5 <= 10x => 15x + 3 <= 10x => 5x <= -3 => x <= -3/5.

г) (y-1)/2 - (2y+3)/8 - y > 2 => (4(y-1) - (2y+3) - 8y)/8 > 2 => 4y - 4 - 2y - 3 - 8y > 16 => -6y - 7 > 16 => -6y > 23 => y < -23/6.