872. 1) \(\left(6\frac{7}{12}-3\frac{11}{36}\right)\cdot2,5-4\frac{1}{3}:0,65\); 2) \(\left(9\frac{1}{5}-3,68\right):2\frac{1}{2}\cdot\left[1:(2,1-2,09)\right]\); 3) \(2,88\cdot\frac{35}{72}+\left(1,0625-\frac{5}{12}\right)\cdot16\); 4) \(\left(1\frac{11}{24}+\frac{13}{36}\right)\cdot1,44-\frac{8}{15}\cdot0,5625\).

1) \(6\frac{7}{12}-3\frac{11}{36}=3\frac{5}{18}=\frac{59}{18}\).

\(\frac{59}{18}\cdot2,5=\frac{59}{18}\cdot\frac52=\frac{295}{36}\).

\(4\frac13:0,65=\frac{13}{3}:\frac{13}{20}=\frac{20}{3}\).

\(\frac{295}{36}-\frac{20}{3}=\frac{55}{36}=1\frac{19}{36}\).

2) \(9\frac15-3,68=5,52\), \(5,52:2\frac12=5,52:2,5=2,208\).

\(2,1-2,09=0,01\), поэтому \(1:0,01=100\).

\(2,208\cdot100=220,8=220\frac45\).

3) \(2,88\cdot\frac{35}{72}=\frac{72}{25}\cdot\frac{35}{72}=\frac75\).

\(1,0625-\frac5{12}=\frac{17}{16}-\frac5{12}=\frac{31}{48}\), поэтому \(\frac{31}{48}\cdot16=\frac{31}{3}\).

\(\frac75+\frac{31}{3}=\frac{176}{15}=11\frac{11}{15}\).

4) \(1\frac{11}{24}+\frac{13}{36}=\frac{131}{72}\), а \(1,44=\frac{36}{25}\).

\(\frac{131}{72}\cdot\frac{36}{25}=\frac{131}{50}\).

\(\frac8{15}\cdot0,5625=\frac8{15}\cdot\frac9{16}=\frac3{10}\).

\(\frac{131}{50}-\frac3{10}=\frac{116}{50}=\frac{58}{25}=2,32\).

Ответ: 1) \(1\frac{19}{36}\); 2) \(220\frac45\); 3) \(11\frac{11}{15}\); 4) \(2,32\).