9) 2^x > 3^x

1. Divide both sides by $$3^x$$ (since $$3^x$$ is always positive): $$(2/3)^x > 1$$

2. Rewrite 1 as a power of $$2/3$$: $$(2/3)^x > (2/3)^0$$

3. Since the base is between 0 and 1, reverse the inequality sign: $$x < 0$$.