927. Запишите в виде произведения:

a) $$-x^3 + y^3 = y^3 - x^3 = (y-x)(y^2+yx+x^2)$$

б) $$-8 - p^3 = -(8+p^3) = -(2^3+p^3) = -(2+p)(4-2p+p^2)$$

в) $$-a^6 + \frac{1}{8} = \frac{1}{8} - a^6 = (\frac{1}{2})^3 - (a^2)^3 = (\frac{1}{2}-a^2)(\frac{1}{4}+\frac{1}{2}a^2+a^4)$$

г) $$-\frac{1}{27} - b^6 = -(\frac{1}{27} + b^6) = - ((\frac{1}{3})^3 + (b^2)^3) = - (\frac{1}{3}+b^2)(\frac{1}{9}-\frac{1}{3}b^2+b^4)$$

д) $$c^6 + 1 = (c^2)^3 + 1^3 = (c^2+1)(c^4-c^2+1)$$

е) $$x^6 + y^6 = (x^2)^3 + (y^2)^3 = (x^2+y^2)(x^4-x^2y^2+y^4)$$