8) 1 5 a²b²+ 2 5 a²b+ 3 5 ab² + 4 5 a²b² =

Для решения необходимо привести подобные слагаемые.

$$\frac{1}{5}a^2b^2 + \frac{2}{5}a^2b + \frac{3}{5}ab^2 + \frac{4}{5}a^2b^2 = (\frac{1}{5}a^2b^2 + \frac{4}{5}a^2b^2) + \frac{2}{5}a^2b + \frac{3}{5}ab^2 = \frac{5}{5}a^2b^2 + \frac{2}{5}a^2b + \frac{3}{5}ab^2 = a^2b^2 + \frac{2}{5}a^2b + \frac{3}{5}ab^2$$

Ответ: $$a^2b^2 + \frac{2}{5}a^2b + \frac{3}{5}ab^2$$