8) 1 a²b2+ a²b+ab² = a²b²=

8) \(\frac{1}{5} a^2b^2 + \frac{2}{5}a^2b + \frac{3}{5}ab^2 + \frac{4}{5}a^2b^2=\)

Приведем подобные члены: \(\frac{1}{5} a^2b^2 + \frac{4}{5}a^2b^2 = \frac{5}{5} a^2b^2 = a^2b^2\)

\(a^2b^2 + \frac{2}{5}a^2b + \frac{3}{5}ab^2\)

Ответ: \(a^2b^2 + \frac{2}{5}a^2b + \frac{3}{5}ab^2\)