2. a) $$(1\frac{7}{15} +2,4):2\frac{1}{14}$$

$$\begin{aligned} &1\frac{7}{15} + 2,4 = 1\frac{7}{15} + 2\frac{4}{10} = 1\frac{7}{15} + 2\frac{2}{5} = 1\frac{7}{15} + 2\frac{6}{15} = 3\frac{13}{15} = \frac{3\cdot 15 + 13}{15} = \frac{45+13}{15} = \frac{58}{15} \\ &2\frac{1}{14} = \frac{2 \cdot 14 + 1}{14} = \frac{28+1}{14} = \frac{29}{14} \\ &\frac{58}{15} : \frac{29}{14} = \frac{58}{15} \cdot \frac{14}{29} = \frac{2 \cdot 29}{15} \cdot \frac{14}{29} = \frac{2}{15} \cdot 14 = \frac{28}{15} = 1\frac{13}{15} \end{aligned}$$ Ответ: $$\bf{1\frac{13}{15}}$$