Для решения необходимо сравнить дроби в каждой паре.
а)
$$\frac{1}{6} = \frac{4}{24}$$
$$\frac{3}{8} = \frac{9}{24}$$
$$\frac{1}{6} < \frac{3}{8}$$
б)
$$\frac{4}{9} = \frac{20}{45}$$
$$\frac{7}{15} = \frac{21}{45}$$
$$\frac{4}{9} < \frac{7}{15}$$
в)
$$\frac{5}{33} = \frac{40}{264}$$
$$\frac{1}{8} = \frac{33}{264}$$
$$\frac{5}{33} > \frac{1}{8}$$
г)
$$\frac{8}{15} = \frac{32}{60}$$
$$\frac{11}{12} = \frac{55}{60}$$
$$\frac{8}{15} < \frac{11}{12}$$
д)
$$\frac{9}{10} = \frac{54}{60}$$
$$\frac{5}{12} = \frac{25}{60}$$
$$\frac{9}{10} > \frac{5}{12}$$
е)
$$\frac{13}{12} = \frac{39}{36}$$
$$\frac{13}{18} = \frac{26}{36}$$
$$\frac{13}{12} > \frac{13}{18}$$
ж)
$$\frac{11}{30} = \frac{33}{90}$$
$$\frac{8}{45} = \frac{16}{90}$$
$$\frac{11}{30} > \frac{8}{45}$$
к)
$$\frac{9}{98} = \frac{9 \cdot 28}{98 \cdot 28} = \frac{252}{2744}$$
$$\frac{5}{56} = \frac{5 \cdot 49}{56 \cdot 49} = \frac{245}{2744}$$
$$\frac{9}{98} > \frac{5}{56}$$
л)
$$\frac{13}{750} = \frac{26}{1500}$$
$$\frac{7}{450} = \frac{23\frac{1}{3}}{1500}$$
$$\frac{13}{750} > \frac{7}{450}$$
м)
$$\frac{10}{297} = \frac{10 \cdot 11}{297 \cdot 11} = \frac{110}{3267}$$
$$\frac{14}{363} = \frac{14 \cdot 9}{363 \cdot 9} = \frac{126}{3267}$$
$$\frac{10}{297} < \frac{14}{363}$$
и)
$$\frac{8}{33} = \frac{8 \cdot 7}{33 \cdot 7} = \frac{56}{231}$$
$$\frac{9}{77} = \frac{9 \cdot 3}{77 \cdot 3} = \frac{27}{231}$$
$$\frac{8}{33} > \frac{9}{77}$$