A triangle has sides of length 6, 8, and 10. What is the area of the triangle?

This is a right-angled triangle since $$6^2 + 8^2 = 36 + 64 = 100 = 10^2$$. The area of a right-angled triangle is $$\frac{1}{2} \times \text{base} \times \text{height}$$.

Ответ: $$24$$