Ответ:
Подставим \(x=0,4=\frac{2}{5}\):
\[\frac{2x+\frac{1}{7}}{3}=\frac{2\cdot\frac{2}{5}+\frac{1}{7}}{3}=\frac{\frac{4}{5}+\frac{1}{7}}{3}=\frac{\frac{28}{35}+\frac{5}{35}}{3}=\frac{33}{35}\cdot\frac{1}{3}=\frac{11}{35}.\]
Ответ: \(\frac{11}{35}\).
