а) \(\frac{1}{6} + \frac{7}{27} \cdot \frac{9}{14} = \frac{1}{6} + \frac{7 \cdot 9}{27 \cdot 14} = \frac{1}{6} + \frac{1 \cdot 1}{3 \cdot 2} = \frac{1}{6} + \frac{1}{6} = \frac{2}{6} = \frac{1}{3}\)
б) (-4 + 6.2) : 11 = 2.2 : 11 = 0.2
Ответ: а) \(\frac{1}{3}\), б) 0.2