Ответ: a) x = ±0.5; б) y = ±1.4; в) a = ±\(\frac{5}{6}\); г) z = ±\(\frac{1}{12}\)
Решение: a) 4x² - 1 = 0 4x² = 1 x² = \(\frac{1}{4}\) x = ±\(\sqrt{\frac{1}{4}}\) = ±\(\frac{1}{2}\) = ±0.5 б) 25y² - 49 = 0 25y² = 49 y² = \(\frac{49}{25}\) y = ±\(\sqrt{\frac{49}{25}}\) = ±\(\frac{7}{5}\) = ±1.4 в) 36a² - 25 = 0 36a² = 25 a² = \(\frac{25}{36}\) a = ±\(\sqrt{\frac{25}{36}}\) = ±\(\frac{5}{6}\) г) 144z² - 1 = 0 144z² = 1 z² = \(\frac{1}{144}\) z = ±\(\sqrt{\frac{1}{144}}\) = ±\(\frac{1}{12}\)
Ответ: a) x = ±0.5; б) y = ±1.4; в) a = ±\(\frac{5}{6}\); г) z = ±\(\frac{1}{12}\)