a) \(x + 4\frac{1}{8} = 5\) б) \(y - 6\frac{1}{4} = 2\frac{1}{3}\) в) \(25\frac{2}{7} + x = 30\)

Решение:

а) \( x + 4\frac{1}{8} = 5 \) \( x = 5 - 4\frac{1}{8} \) \( x = \frac{40}{8} - \frac{33}{8} \) \( x = \frac{7}{8} \)

б) \( y - 6\frac{1}{4} = 2\frac{1}{3} \) \( y = 2\frac{1}{3} + 6\frac{1}{4} \) \( y = \frac{7}{3} + \frac{25}{4} \) \( y = \frac{28 + 75}{12} \) \( y = \frac{103}{12} = 8\frac{7}{12} \)

в) \( 25\frac{2}{7} + x = 30 \) \( x = 30 - 25\frac{2}{7} \) \( x = \frac{210}{7} - \frac{177}{7} \) \( x = \frac{33}{7} = 4\frac{5}{7} \)

Ответ: а) \( x = \frac{7}{8} \), б) \( y = 8\frac{7}{12} \), в) \( x = 4\frac{5}{7} \).