4 0 a) 4(2-3x)+7(6x+1)-9(9x+4)=30; б) 17-2(x+3)+5(x-7)-3(2x+1)=-28; в) х(4х+11)-7 (x²-5x)=-3x(x+3);

а)

\[4(2-3x)+7(6x+1)-9(9x+4)=30\]

\[8 - 12x + 42x + 7 - 81x - 36 = 30\]

\[-12x + 42x - 81x = 30 - 8 - 7 + 36\]

\[-51x = 51\]

\[x = -1\]

б)

\[17-2(x+3)+5(x-7)-3(2x+1)=-28\]

\[17 - 2x - 6 + 5x - 35 - 6x - 3 = -28\]

\[-2x + 5x - 6x = -28 - 17 + 6 + 35 + 3\]

\[-3x = -1\]

\[x = \frac{1}{3}\]

в)

\[x(4x+11)-7(x^2-5x)=-3x(x+3)\]

\[4x^2 + 11x - 7x^2 + 35x = -3x^2 - 9x\]

\[4x^2 - 7x^2 + 3x^2 + 11x + 35x + 9x = 0\]

\[0x^2 + 55x = 0\]

\[55x = 0\]

\[x = 0\]

Ответ: а) -1, б) \(\frac{1}{3}\), в) 0