2) AB = 2, DC-3

Дано: AB = 2, DC = 3

$$S_{полн} = S_{бок} + S_{O} = 3\sqrt{3} + 8$$ $$SO = 2 \cdot 3 = 6$$ $$S_{бок} = P \cdot L = 3\sqrt{3}$$ $$l^2 = 2^2 - 1^2 = 3 \Rightarrow l = \sqrt{3}$$ $$(2:2)^2 = 3 - 1 = 8 = \sqrt{8}$$

Ответ: $$\sqrt{8}$$