a=8,b=6,c=10 sin A= cos A= tg A= sin B= cos B= tg B=

Решение:

Рассмотрим прямоугольный треугольник ABC, где:

• a = BC = 8
• b = AC = 6
• c = AB = 10

1. sin A = \(\frac{CA}{BA} = \frac{6}{10} = \frac{3}{5} = 0.6\)
2. cos A = \(\frac{BC}{BA} = \frac{8}{10} = \frac{4}{5} = 0.8\)
3. tg A = \(\frac{CA}{BC} = \frac{6}{8} = \frac{3}{4} = 0.75\)
4. sin B = \(\frac{BC}{AB} = \frac{8}{10} = \frac{4}{5} = 0.8\)
5. cos B = \(\frac{AC}{AB} = \frac{6}{10} = \frac{3}{5} = 0.6\)
6. tg B = \(\frac{AC}{BC} = \frac{6}{8} = \frac{3}{4} = 0.75\)