6.33. 1) a-x+b+x; m 2) a-3b+4b-a; n

1) \[\frac{a-x}{m} + \frac{b+x}{m} = \frac{a - x + b + x}{m} = \frac{a+b}{m}\]

2) \[\frac{a-3b}{n} + \frac{4b-a}{n} = \frac{a - 3b + 4b - a}{n} = \frac{b}{n}\]

Ответ: 1) \(\frac{a+b}{m}\); 2) \(\frac{b}{n}\)