б) \(\frac{2}{8}\cdot\frac{8}{8}+(3\frac{1}{3}-2\frac{3}{5}):\frac{7}{15}\)

б) \(\frac{2}{8}\cdot\frac{8}{8}+(3\frac{1}{3}-2\frac{3}{5}):\frac{7}{15}=\frac{1}{4}+(\frac{10}{3}-\frac{13}{5}):\frac{7}{15}=\frac{1}{4}+(\frac{50-39}{15}):\frac{7}{15}=\frac{1}{4}+\frac{11}{15}:\frac{7}{15}=\frac{1}{4}+\frac{11}{15}\cdot\frac{15}{7}=\frac{1}{4}+\frac{11}{7}=\frac{7+44}{28}=\frac{51}{28}=1\frac{23}{28}\)

Ответ: 51/28