б) $$(1-\frac{11}{17}) \cdot (\frac{3}{4} - \frac{5}{12} + \frac{11}{18}) =$$

Решим пример по действиям:

1. $$1 - \frac{11}{17} = \frac{17}{17} - \frac{11}{17} = \frac{17-11}{17} = \frac{6}{17}$$
2. $$\frac{3}{4} - \frac{5}{12} + \frac{11}{18} = \frac{3 \cdot 9}{4 \cdot 9} - \frac{5 \cdot 3}{12 \cdot 3} + \frac{11 \cdot 2}{18 \cdot 2} = \frac{27}{36} - \frac{15}{36} + \frac{22}{36} = \frac{27-15+22}{36} = \frac{34}{36} = \frac{17}{18}$$
3. $$\frac{6}{17} \cdot \frac{17}{18} = \frac{6 \cdot 17}{17 \cdot 18} = \frac{6}{18} = \frac{1}{3}$$

Ответ: $$\frac{1}{3}$$