б) √108. √12 ;б) √75 192'

б) $$ \frac{\sqrt{108}}{\sqrt{12}} = \sqrt{\frac{108}{12}} = \sqrt{9} = 3 $$.

б) $$ \frac{\sqrt{75}}{\sqrt{192}} = \sqrt{\frac{75}{192}} = \sqrt{\frac{25 \cdot 3}{64 \cdot 3}} = \sqrt{\frac{25}{64}} = \frac{\sqrt{25}}{\sqrt{64}} = \frac{5}{8} $$.

Ответ: б) 3; б) 5/8