B 1) 1) 1 1. (√2-3) √2-3 12-36) = √2+3 (12+3) (√2-3)22-92-7

1) $$\frac{1}{\sqrt{2}+3} = \frac{1 \cdot (\sqrt{2}-3)}{(\sqrt{2}+3) \cdot (\sqrt{2}-3)} = \frac{\sqrt{2}-3}{2-9} = \frac{\sqrt{2}-3}{-7} = \frac{3-\sqrt{2}}{7}$$

Ответ: $$\frac{3-\sqrt{2}}{7}$$