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МатематикаВопрос:
B. 1) 35 25 59 9 7)-1- 13)-1- 2) 12. 29 29 (음)-8)-- 9 = 14)-2247- 70 12.12+5.29-144 29.12 1229-34 +145289 348 348 25 = 3)-15 28 9) 4) -(-)(6 15) 15(9)- 93 9 35 10 36 10)-(-2)- 16)-772- 5 5 حمد 6) 10 11)-7- = 17) 28 3 69 6 12 35 116 35 4 22 18) 6 = 11 35
Ответ:
Краткое пояснение: Решаем представленные примеры на сложение, вычитание, умножение и деление дробей.
1) \[\frac{3}{25} \cdot \frac{5}{9} = \frac{3 \cdot 5}{25 \cdot 9} = \frac{1 \cdot 1}{5 \cdot 3} = \frac{1}{15}\]
2) \[12 \cdot (\frac{5}{29} - \frac{12}{29}) = 12 \cdot (\frac{5 - 12}{29}) = 12 \cdot (\frac{-7}{29}) = -\frac{12 \cdot 7}{29} = -\frac{84}{29} = -2 \frac{26}{29}\]
3) \[-\frac{14}{15} - \frac{25}{28} = -\frac{14 \cdot 28}{15 \cdot 28} - \frac{25 \cdot 15}{28 \cdot 15} = -\frac{392}{420} - \frac{375}{420} = -\frac{392 + 375}{420} = -\frac{767}{420} = -1 \frac{347}{420}\]
4) \[\frac{9}{10} - \frac{35}{36} = \frac{9 \cdot 18}{10 \cdot 18} - \frac{35 \cdot 5}{36 \cdot 5} = \frac{162}{180} - \frac{175}{180} = \frac{162 - 175}{180} = \frac{-13}{180} = -\frac{13}{180}\]
5) \[\frac{8}{15} \cdot (-\frac{9}{28}) = -\frac{8 \cdot 9}{15 \cdot 28} = -\frac{2 \cdot 3}{5 \cdot 7} = -\frac{6}{35}\]
6) \[\frac{5}{12} \cdot (-\frac{6}{35}) = -\frac{5 \cdot 6}{12 \cdot 35} = -\frac{1 \cdot 1}{2 \cdot 7} = -\frac{1}{14}\]
7) \[-1 \frac{1}{6} \cdot \frac{2}{9} = -\frac{7}{6} \cdot \frac{2}{9} = -\frac{7 \cdot 2}{6 \cdot 9} = -\frac{7 \cdot 1}{3 \cdot 9} = -\frac{7}{27}\]
8) \[-\frac{4}{7} \cdot 1 \frac{1}{2} = -\frac{4}{7} \cdot \frac{3}{2} = -\frac{4 \cdot 3}{7 \cdot 2} = -\frac{2 \cdot 3}{7 \cdot 1} = -\frac{6}{7}\]
9) \[\frac{3}{10} \cdot (-3 \frac{1}{3}) = \frac{3}{10} \cdot (-\frac{10}{3}) = -\frac{3 \cdot 10}{10 \cdot 3} = -\frac{1 \cdot 1}{1 \cdot 1} = -1\]
10) \[\frac{2}{9} \cdot (-2 \frac{1}{4}) = \frac{2}{9} \cdot (-\frac{9}{4}) = -\frac{2 \cdot 9}{9 \cdot 4} = -\frac{1 \cdot 1}{1 \cdot 2} = -\frac{1}{2}\]
11) \[1 \frac{1}{11} - \frac{7}{3} = \frac{12}{11} - \frac{7}{3} = \frac{12 \cdot 3}{11 \cdot 3} - \frac{7 \cdot 11}{3 \cdot 11} = \frac{36}{33} - \frac{77}{33} = \frac{36 - 77}{33} = \frac{-41}{33} = -1 \frac{8}{33}\]
12) \[\frac{5}{13} \cdot (-1 \frac{6}{7}) = \frac{5}{13} \cdot (-\frac{13}{7}) = -\frac{5 \cdot 13}{13 \cdot 7} = -\frac{5 \cdot 1}{1 \cdot 7} = -\frac{5}{7}\]
13) \[-\frac{3}{16} - \frac{1}{3} = -\frac{3 \cdot 3}{16 \cdot 3} - \frac{1 \cdot 16}{3 \cdot 16} = -\frac{9}{48} - \frac{16}{48} = \frac{-9 - 16}{48} = \frac{-25}{48} = -\frac{25}{48}\]
14) \[-2 \frac{1}{24} + \frac{9}{70} = -\frac{49}{24} + \frac{9}{70} = -\frac{49 \cdot 35}{24 \cdot 35} + \frac{9 \cdot 12}{70 \cdot 12} = -\frac{1715}{840} + \frac{108}{840} = \frac{-1715 + 108}{840} = \frac{-1607}{840} = -1 \frac{767}{840}\]
15) \[15 \frac{1}{2} - (-\frac{5}{93}) = \frac{31}{2} + \frac{5}{93} = \frac{31 \cdot 93}{2 \cdot 93} + \frac{5 \cdot 2}{93 \cdot 2} = \frac{2883}{186} + \frac{10}{186} = \frac{2883 + 10}{186} = \frac{2893}{186} = 15 \frac{103}{186}\]
16) \[-7 \frac{1}{5} + \frac{7}{72} = -\frac{36}{5} + \frac{7}{72} = -\frac{36 \cdot 72}{5 \cdot 72} + \frac{7 \cdot 5}{72 \cdot 5} = -\frac{2592}{360} + \frac{35}{360} = \frac{-2592 + 35}{360} = \frac{-2557}{360} = -7 \frac{37}{360}\]
17) \[\frac{10}{69} \cdot (-\frac{4}{5}) = -\frac{10 \cdot 4}{69 \cdot 5} = -\frac{2 \cdot 4}{69 \cdot 1} = -\frac{8}{69}\]
18) \[6 \frac{4}{11} \cdot (-\frac{22}{35}) = \frac{70}{11} \cdot (-\frac{22}{35}) = -\frac{70 \cdot 22}{11 \cdot 35} = -\frac{2 \cdot 2}{1 \cdot 1} = -4\]
Ответ: Решения выше
