Вопрос:

Б. 1) 11 20 - 11 20 = 2) 4 35 - 4 35 = 3) 3 4 - 1 4 = 4) 7 9 - 1 9 = 5) 15 16 - 5 16 = 6) 2- 3 5 - 1 5 = 7) 2- 6 11 = 8) 5- 10 13 = 9) 18- 12 13 = 10) 4- 8 27 = 11) 3:- 3 4 = 12) 10:- 5 7 = 13) 6:- 1 5 = 14) 1:- 1 7 = 15) 1:- 1 2 = Задание 129. Выполните действия. A. 1) 9 2 5 : 6 15 : 8 15 = 2.6 9 : 6 5 : 8 15 = 22 3 : 8 5 = 6) 33 16 64 : 27 3 : 4 44 = 5 1) 15 4 15 : 4 8 = 15 : 1 15 = 1.1 1.2 : 1 2 = 2) 7 3 10 : 3 14 = 7) 33 4 14 : 121 42 : 55 3 = 3) 28 11 5 : 2 55 : 16 = 8) 25 5 18 : 4 36 : 7 = 4) 36 11 9 : 2 77 : 8 = 9) 49 81 51 : 6 17 : 42 3 = 5) 35 18 21 : 5 49 : 36 = 10) 39: 27 26 22 : 75 54 : 5 = 116

Смотреть решения всех заданий с листа

Ответ:

{ "Б": { "1)": "\[\frac{11}{20} - \frac{11}{20} = 0\]", "2)": "\[\frac{4}{35} - \frac{4}{35} = 0\]", "3)": "\[\frac{3}{4} : \frac{1}{4} = \frac{3}{4} \cdot \frac{4}{1} = 3\]", "4)": "\[\frac{7}{9} - \frac{1}{9} = \frac{6}{9} = \frac{2}{3}\]", "5)": "\[\frac{15}{16} - \frac{5}{16} = \frac{10}{16} = \frac{5}{8}\]", "6)": "\[2 \frac{3}{5} - \frac{1}{5} = \frac{13}{5} - \frac{1}{5} = \frac{12}{5} = 2 \frac{2}{5}\]", "7)": "\[2 \frac{6}{11} = \frac{28}{11}\]", "8)": "\[5 - \frac{10}{13} = \frac{65}{13} - \frac{10}{13} = \frac{55}{13} = 4 \frac{3}{13}\]", "9)": "\[18 - \frac{12}{13} = \frac{234}{13} - \frac{12}{13} = \frac{222}{13} = 17 \frac{1}{13}\]", "10)": "\[4 - \frac{8}{27} = \frac{108}{27} - \frac{8}{27} = \frac{100}{27} = 3 \frac{19}{27}\]", "11)": "\[3 : \frac{3}{4} = \frac{3}{1} \cdot \frac{4}{3} = 4\]", "12)": "\[10 : \frac{5}{7} = \frac{10}{1} \cdot \frac{7}{5} = \frac{70}{5} = 14\]", "13)": "\[6 : \frac{1}{5} = \frac{6}{1} \cdot \frac{5}{1} = 30\]", "14)": "\[1 : \frac{1}{7} = \frac{1}{1} \cdot \frac{7}{1} = 7\]", "15)": "\[1 : \frac{1}{2} = \frac{1}{1} \cdot \frac{2}{1} = 2\]" }, "A": { "1)": "\[\frac{2}{9} : \frac{6}{5} : \frac{8}{15} = \frac{2}{9} \cdot \frac{5}{6} \cdot \frac{15}{8} = \frac{2 \cdot 5 \cdot 15}{9 \cdot 6 \cdot 8} = \frac{150}{432} = \frac{25}{72}\]", "2)": "\[\frac{3}{7} : \frac{3}{10} : \frac{9}{14} = \frac{3}{7} \cdot \frac{10}{3} \cdot \frac{14}{9} = \frac{3 \cdot 10 \cdot 14}{7 \cdot 3 \cdot 9} = \frac{420}{189} = \frac{20}{9} = 2 \frac{2}{9}\]", "3)": "\[\frac{11}{28} : \frac{2}{5} : \frac{16}{55} = \frac{11}{28} \cdot \frac{5}{2} \cdot \frac{55}{16} = \frac{11 \cdot 5 \cdot 55}{28 \cdot 2 \cdot 16} = \frac{3025}{896} = 3 \frac{337}{896}\]", "4)": "\[\frac{11}{36} : \frac{2}{9} : \frac{8}{77} = \frac{11}{36} \cdot \frac{9}{2} \cdot \frac{77}{8} = \frac{11 \cdot 9 \cdot 77}{36 \cdot 2 \cdot 8} = \frac{7623}{576} = \frac{2541}{192} = 13 \frac{45}{192} = 13 \frac{15}{64}\]", "5)": "\[\frac{18}{35} : \frac{5}{21} : \frac{36}{49} = \frac{18}{35} \cdot \frac{21}{5} \cdot \frac{49}{36} = \frac{18 \cdot 21 \cdot 49}{35 \cdot 5 \cdot 36} = \frac{18522}{6300} = \frac{3087}{1050} = \frac{1029}{350} = 2 \frac{329}{350}\]", "6)": "\[\frac{16}{33} : \frac{27}{64} : \frac{4}{3} : \frac{5}{44} = \frac{16}{33} \cdot \frac{64}{27} \cdot \frac{3}{4} \cdot \frac{44}{5} = \frac{16 \cdot 64 \cdot 3 \cdot 44}{33 \cdot 27 \cdot 4 \cdot 5} = \frac{135168}{17820} = \frac{3754 \frac{2}{3}}{495}\]", "7)": "\[\frac{4}{33} : \frac{121}{14} : \frac{55}{42} : 3 = \frac{4}{33} \cdot \frac{14}{121} \cdot \frac{42}{55} \cdot \frac{1}{3} = \frac{4 \cdot 14 \cdot 42 \cdot 1}{33 \cdot 121 \cdot 55 \cdot 3} = \frac{2352}{653445} = \frac{784}{217815}\]", "8)": "\[5 : \frac{4}{25} : \frac{7}{18} : \frac{28}{36} = \frac{5}{1} \cdot \frac{25}{4} \cdot \frac{18}{7} \cdot \frac{36}{28} = \frac{5 \cdot 25 \cdot 18 \cdot 36}{1 \cdot 4 \cdot 7 \cdot 28} = \frac{81000}{784} = \frac{20250}{196} = \frac{10125}{98} = 103 \frac{31}{98}\]", "9)": "\[\frac{81}{49} : 6 : \frac{42}{51} : \frac{3}{17} = \frac{81}{49} \cdot \frac{1}{6} \cdot \frac{51}{42} \cdot \frac{17}{3} = \frac{81 \cdot 1 \cdot 51 \cdot 17}{49 \cdot 6 \cdot 42 \cdot 3} = \frac{70467}{3087 \frac{2}{3}} = \frac{70467}{6 \frac{3}{4}}\]", "10)": "\[39 : \frac{26}{27} : \frac{75}{22} : \frac{5}{54} = \frac{39}{1} \cdot \frac{27}{26} \cdot \frac{22}{75} \cdot \frac{54}{5} = \frac{39 \cdot 27 \cdot 22 \cdot 54}{1 \cdot 26 \cdot 75 \cdot 5} = \frac{1380744}{9750} = \frac{230124}{1625} = 141 \frac{199}{1625}\]" } }

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