Вопрос:

б) \((1\frac{11}{24}+\frac{13}{36})\cdot1,44-\frac{8}{15}\\cdot0,5625\)

Ответ:

\[\left(1\frac{11}{24}+\frac{13}{36}\right)\cdot1.44-\frac{8}{15}\cdot0.5625\]

\[1\frac{11}{24}=\frac{35}{24},\qquad 1.44=\frac{36}{25},\qquad 0.5625=\frac{9}{16}.\]

\[\left(\frac{35}{24}+\frac{13}{36}\right)\cdot\frac{36}{25}-\frac{8}{15}\cdot\frac{9}{16}\]

\[\left(\frac{105}{72}+\frac{26}{72}\right)\cdot\frac{36}{25}-\frac{3}{10}=\frac{131}{72}\cdot\frac{36}{25}-\frac{3}{10}\]

\[\frac{131}{50}-\frac{15}{50}=\frac{116}{50}=\frac{58}{25}=2.32.\]

Ответ: 2,32.