b) 2 3/5, 1 1/6, 6 3/9, 3 7/11, 7 5/12

Решение: \(2\frac{3}{5} = \frac{5*2 + 3}{5} = \frac{13}{5}\) \(1\frac{1}{6} = \frac{6*1 + 1}{6} = \frac{7}{6}\) \(6\frac{3}{9} = \frac{9*6 + 3}{9} = \frac{57}{9} = \frac{19}{3}\) \(3\frac{7}{11} = \frac{11*3 + 7}{11} = \frac{40}{11}\) \(7\frac{5}{12} = \frac{12*7 + 5}{12} = \frac{89}{12}\) Ответ: \(\frac{13}{5}, \frac{7}{6}, \frac{19}{3}, \frac{40}{11}, \frac{89}{12}\)