Ответ:

Используем равенство \(3k=7\).

  1. \(6k=2\cdot3k=2\cdot7=14\).
  2. \(\dfrac{3k}{10}=\dfrac{7}{10}\).
  3. \(\dfrac{3k}{20}=\dfrac{7}{20}\).
  4. \(3k+4=7+4=11\).
  5. \(9k=3\cdot3k=3\cdot7=21\).
  6. \(\dfrac{7.7}{3k}=\dfrac{7.7}{7}=1.1\).
  7. \(50-9k=50-21=29\).
  8. \(\dfrac{1}{-3k}=\dfrac{1}{-7}=-\dfrac{1}{7}\).
  9. \(2k=\dfrac{2}{3}\cdot3k=\dfrac{2}{3}\cdot7=\dfrac{14}{3}\).
  10. \(\dfrac{1}{5k}=\dfrac{1}{\frac{5}{3}\cdot3k}=\dfrac{1}{\frac{35}{3}}=\dfrac{3}{35}\).

Ответ: 1) 14; 2) \(\frac{7}{10}\); 3) \(\frac{7}{20}\); 4) 11; 5) 21; 6) 1,1; 7) 29; 8) \(-\frac{1}{7}\); 9) \(\frac{14}{3}\); 10) \(\frac{3}{35}\).