БЛОК №2. Найдите значение выражения. №1: (1/30 + 1/42) : 1/7; №2: (1/18 − 1/21) : 5/63; №3: (1/35 − 1/60) : 1/21; №4: (1/72 − 1/99) : 5/33; №5: (1/24 + 1/56) : 20/21; №6: 6 · (1/3)² − 17 · 1/3; №7: 9 · (1/9)² − 19 · 1/9; №8: 21 · (1/7)² − 10 · 1/7; №9: 18 · (1/9)² − 20 · 1/9; №10: 14 · (1/7)² − 23 · 1/7; №11: (1/13 − 2 3/4) : 1/26; №12: (5/6 + 1 1/10) : 1/24; №13: (4/9 − 3 1/15) : 1/9; №14: (1 5/6 + 3/5) : 1/24; №15: 1 1/12 : (1 13/18 − 2 5/9); №16: (17/26 + 11/13) : 6/17; №17: 3.5 : (2 − 4/9).

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Accepted Answer

\(\left(\frac{1}{30}+\frac{1}{42}\right):\frac{1}{7}=\frac{2}{5}\).
\(\left(\frac{1}{18}-\frac{1}{21}\right):\frac{5}{63}=\frac{1}{10}\).
\(\left(\frac{1}{35}-\frac{1}{60}\right):\frac{1}{21}=\frac{1}{4}\).
\(\left(\frac{1}{72}-\frac{1}{99}\right):\frac{5}{33}=\frac{1}{40}\).
\(\left(\frac{1}{24}+\frac{1}{56}\right):\frac{20}{21}=\frac{1}{16}\).
\(6\cdot\left(\frac{1}{3}\right)^2-17\cdot\frac{1}{3}=-5\).
\(9\cdot\left(\frac{1}{9}\right)^2-19\cdot\frac{1}{9}=-2\).
\(21\cdot\left(\frac{1}{7}\right)^2-10\cdot\frac{1}{7}=-1\).
\(18\cdot\left(\frac{1}{9}\right)^2-20\cdot\frac{1}{9}=-2\).
\(14\cdot\left(\frac{1}{7}\right)^2-23\cdot\frac{1}{7}=-3\).
\(\left(\frac{1}{13}-2\frac{3}{4}\right):\frac{1}{26}=-\frac{139}{2}\).
\(\left(\frac{5}{6}+1\frac{1}{10}\right):\frac{1}{24}=40\).
\(\left(\frac{4}{9}-3\frac{1}{15}\right):\frac{1}{9}=-\frac{118}{5}\).
\(\left(1\frac{5}{6}+\frac{3}{5}\right):\frac{1}{24}=\frac{292}{5}\).
\(1\frac{1}{12}:\left(1\frac{13}{18}-2\frac{5}{9}\right)=-\frac{13}{10}\).
\(\left(\frac{17}{26}+\frac{11}{13}\right):\frac{6}{17}=\frac{17}{4}\).
\(3.5:\left(2-\frac{4}{9}\right)=\frac{9}{4}\).

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