Magic Square 1:
This is a 3x3 magic square. We are given some numbers and need to fill in the missing ones. In a magic square, the sum of the numbers in each row, each column, and each of the two main diagonals is the same.
Let's analyze the given numbers:
Row 1: _, 6, _
Row 2: _, _, _
Row 3: 12, 22, 8
Column 1: _, _, 12
Column 2: 6, _, 22
Column 3: _, _, 8
Diagonal 1: _, _, 8
Diagonal 2: _, _, 12
From the third row, we can calculate the magic sum. Sum of Row 3 = 12 + 22 + 8 = 42.
So, the magic sum is 42.
Filling the square:
- Row 1, Column 1: Let the top-left be x. We know x + 6 + y = 42. We also know x + z + 12 = 42. And x + w + 8 = 42 (diagonal).
- Row 3, Column 3: 8 is given.
- Row 3, Column 2: 22 is given.
- Row 3, Column 1: 12 is given.
- Column 2, Row 1: 6 is given.
- Column 2, Row 3: 22 is given.
- Column 3, Row 3: 8 is given.
- Row 1, Column 2: 6 is given.
- Row 3, Column 2: 22 is given.
- Column 2, Row 1: Let the top middle be 'a'. Then a + b + 22 = 42 (column 2). So a+b=20.
- Row 1, Column 1: Let this be 'x'. Then x + 6 + ? = 42.
- Row 1, Column 3: Let this be 'y'. Then ? + ? + y = 42.
- Row 2, Column 1: Let this be 'z'. Then 12 + z + ? = 42.
- Row 2, Column 2: Let this be 'w'. Then 6 + w + 22 = 42. So w = 42 - 28 = 14.
- Row 2, Column 3: Let this be 'k'. Then ? + k + 8 = 42.
- Diagonal 1 (top-left to bottom-right): x + w + 8 = 42. Since w = 14, x + 14 + 8 = 42 => x + 22 = 42 => x = 20.
- Row 1, Column 1: x = 20.
- Row 1, Column 2: 6 is given.
- Row 1, Column 3: 20 + 6 + y = 42 => 26 + y = 42 => y = 16.
- Row 2, Column 1: z. 20 + z + 12 = 42 => 32 + z = 42 => z = 10.
- Row 2, Column 3: k. 16 + k + 8 = 42 => 24 + k = 42 => k = 18.
The completed magic square is:
Let's check: Rows: 20+6+16=42, 10+14+18=42, 12+22+8=42. Columns: 20+10+12=42, 6+14+22=42, 16+18+8=42. Diagonals: 20+14+8=42, 16+14+12=42.
Magic Square 2:
This is another 3x3 magic square. The numbers given are:
Row 1: _, _, 106
Row 2: _, _, _
Row 3: 112, 122, 108
Let's find the magic sum from Row 3: 112 + 122 + 108 = 342.
So, the magic sum is 342.
Filling the square:
- Row 3, Column 1: 112 is given.
- Row 3, Column 2: 122 is given.
- Row 3, Column 3: 108 is given.
- Row 1, Column 3: 106 is given.
- Column 1, Row 3: 112 is given.
- Column 2, Row 3: 122 is given.
- Column 3, Row 3: 108 is given.
- Column 3, Row 1: 106 is given.
- Column 1, Row 1: Let this be 'a'. Then a + ? + 112 = 342 (Column 1).
- Column 2, Row 1: Let this be 'b'. Then b + ? + 122 = 342 (Column 2).
- Column 3, Row 1: 106 is given.
- Row 1, Column 1: Let this be 'a'. Then a + b + 106 = 342 (Row 1).
- Row 2, Column 1: Let this be 'c'. Then 112 + c + ? = 342 (Column 1).
- Row 2, Column 2: Let this be 'd'. Then 122 + d + ? = 342 (Column 2).
- Row 2, Column 3: Let this be 'e'. Then 106 + e + 108 = 342 (Row 2). So, 214 + e = 342 => e = 342 - 214 = 128.
- Row 2, Column 2: d. 122 + d + 128 = 342 => 250 + d = 342 => d = 342 - 250 = 92.
- Row 2, Column 1: c. 112 + c + 112 (assuming bottom left is repeated for middle row first column, this is incorrect. Let's re-evaluate)
- Let's use diagonals and columns/rows to solve. Magic Sum = 342.
- Row 1: a + b + 106 = 342 => a + b = 236
- Column 1: a + c + 112 = 342 => a + c = 230
- Column 2: b + d + 122 = 342 => b + d = 220
- Column 3: 106 + e + 108 = 342 => e = 128 (as calculated before)
- Diagonal 1 (top-left to bottom-right): a + d + 108 = 342 => a + d = 234
- Diagonal 2 (top-right to bottom-left): 106 + d + 112 = 342 => 218 + d = 342 => d = 342 - 218 = 124.
- Now we have 'd', we can find 'b': b + 124 = 220 => b = 220 - 124 = 96.
- Now we have 'b', we can find 'a': a + 96 = 236 => a = 236 - 96 = 140.
- Now we have 'a', we can find 'c': 140 + c = 230 => c = 230 - 140 = 90.
The completed magic square is:
| 140 |
96 |
106 |
| 90 |
124 |
128 |
| 112 |
122 |
108 |
Let's check: Rows: 140+96+106=342, 90+124+128=342, 112+122+108=342. Columns: 140+90+112=342, 96+124+122=342, 106+128+108=342. Diagonals: 140+124+108=342, 106+124+112=342.