9. ctgt - √3=0

9. ctg t - √3=0

Решение:

$$ctg \; t - \sqrt{3} = 0$$

$$ctg \; t = \sqrt{3}$$

$$t = arcctg \; (\sqrt{3}) + \pi n, n \in Z$$

$$t = \frac{\pi}{6} + \pi n, n \in Z$$

Ответ: $$t = \frac{\pi}{6} + \pi n, n \in Z$$