д) (5√7-13)(5√7+13); e) (2√2 + 3√3)(2√2-3√3); ж) (6-√2)² + 3√32; 3) (√2 + √18)² – 30.

Решим примеры: д) $$(5\sqrt{7}-13)(5\sqrt{7}+13) = (5\sqrt{7})^2 - 13^2 = 25 \cdot 7 - 169 = 175 - 169 = 6$$ е) $$(2\sqrt{2} + 3\sqrt{3})(2\sqrt{2} - 3\sqrt{3}) = (2\sqrt{2})^2 - (3\sqrt{3})^2 = 4 \cdot 2 - 9 \cdot 3 = 8 - 27 = -19$$ ж) $$(6-\sqrt{2})^2 + 3\sqrt{32} = 6^2 - 2 \cdot 6 \cdot \sqrt{2} + (\sqrt{2})^2 + 3\sqrt{16 \cdot 2} = 36 - 12\sqrt{2} + 2 + 3 \cdot 4\sqrt{2} = 38 - 12\sqrt{2} + 12\sqrt{2} = 38$$ з) $$(\sqrt{2} + \sqrt{18})^2 - 30 = (\sqrt{2})^2 + 2 \cdot \sqrt{2} \cdot \sqrt{18} + (\sqrt{18})^2 - 30 = 2 + 2\sqrt{36} + 18 - 30 = 2 + 2 \cdot 6 + 18 - 30 = 2 + 12 + 18 - 30 = 32 - 30 = 2$$ Ответ: д) $$6$$ е) $$-19$$ ж) $$38$$ з) $$2$$