Вопрос:

Д3-1 Решение уравнений М-6 ВАРИАНТ 2 1) -7(5 – x) = 9. 2) -6(3 - x) = 25. 3) -8(4 - x) = 4. 4) 4 = 7 - 6(5x - 1). 5) 5 = 12 - 5(4x - 1). 6) x - 2(3x + 2) = 16. 7) 10 - 5(2x - 1) = 7. 8) 5 + 2x = 3(2x - 5) - 8. 9) 5(x - 3,6) = 9x. 10) 2(7x + 11) - 5x = 5x.

Ответ:

Решение уравнений (Вариант 2):

  1. 1)\[ -7(5 - x) = 9 \]\[ -35 + 7x = 9 \]\[ 7x = 9 + 35 \]\[ 7x = 44 \]\[ x = \frac{44}{7} \]
  2. 2)\[ -6(3 - x) = 25 \]\[ -18 + 6x = 25 \]\[ 6x = 25 + 18 \]\[ 6x = 43 \]\[ x = \frac{43}{6} \]
  3. 3)\[ -8(4 - x) = 4 \]\[ -32 + 8x = 4 \]\[ 8x = 4 + 32 \]\[ 8x = 36 \]\[ x = \frac{36}{8} = \frac{9}{2} = 4.5 \]
  4. 4)\[ 4 = 7 - 6(5x - 1) \]\[ 4 = 7 - 30x + 6 \]\[ 4 = 13 - 30x \]\[ 30x = 13 - 4 \]\[ 30x = 9 \]\[ x = \frac{9}{30} = \frac{3}{10} = 0.3 \]
  5. 5)\[ 5 = 12 - 5(4x - 1) \]\[ 5 = 12 - 20x + 5 \]\[ 5 = 17 - 20x \]\[ 20x = 17 - 5 \]\[ 20x = 12 \]\[ x = \frac{12}{20} = \frac{3}{5} = 0.6 \]
  6. 6)\[ x - 2(3x + 2) = 16 \]\[ x - 6x - 4 = 16 \]\[ -5x - 4 = 16 \]\[ -5x = 16 + 4 \]\[ -5x = 20 \]\[ x = -4 \]
  7. 7)\[ 10 - 5(2x - 1) = 7 \]\[ 10 - 10x + 5 = 7 \]\[ 15 - 10x = 7 \]\[ 15 - 7 = 10x \]\[ 8 = 10x \]\[ x = \frac{8}{10} = 0.8 \]
  8. 8)\[ 5 + 2x = 3(2x - 5) - 8 \]\[ 5 + 2x = 6x - 15 - 8 \]\[ 5 + 2x = 6x - 23 \]\[ 5 + 23 = 6x - 2x \]\[ 28 = 4x \]\[ x = 7 \]
  9. 9)\[ 5(x - 3.6) = 9x \]\[ 5x - 18 = 9x \]\[ -18 = 9x - 5x \]\[ -18 = 4x \]\[ x = \frac{-18}{4} = -4.5 \]
  10. 10)\[ 2(7x + 11) - 5x = 5x \]\[ 14x + 22 - 5x = 5x \]\[ 9x + 22 = 5x \]\[ 22 = 5x - 9x \]\[ 22 = -4x \]\[ x = \frac{22}{-4} = -5.5 \]
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