Решение:
1) \[\frac{3}{7} + \frac{3}{4} : \frac{1}{3} = \frac{3}{7} + \frac{3}{4} \cdot \frac{3}{1} = \frac{3}{7} + \frac{9}{4} = \frac{3 \cdot 4}{7 \cdot 4} + \frac{9 \cdot 7}{4 \cdot 7} = \frac{12}{28} + \frac{63}{28} = \frac{12+63}{28} = \frac{75}{28} = 2\frac{19}{28}\]
2) \[\frac{46}{\frac{2}{3} + \frac{3}{7}} = 46 : (\frac{2}{3} + \frac{3}{7}) = 46 : (\frac{2 \cdot 7}{3 \cdot 7} + \frac{3 \cdot 3}{7 \cdot 3}) = 46 : (\frac{14}{21} + \frac{9}{21}) = 46 : \frac{23}{21} = 46 \cdot \frac{21}{23} = 2 \cdot 21 = 42\]
3) \[\frac{16}{27} \cdot 2\frac{3}{16} - 3\frac{2}{3} = \frac{16}{27} \cdot \frac{35}{16} - \frac{11}{3} = \frac{1}{27} \cdot 35 - \frac{11}{3} = \frac{35}{27} - \frac{11}{3} = \frac{35}{27} - \frac{11 \cdot 9}{3 \cdot 9} = \frac{35}{27} - \frac{99}{27} = \frac{35-99}{27} = \frac{-64}{27} = -2\frac{10}{27}\]
4) \[\frac{15}{16} \cdot 3\frac{3}{5} - 7\frac{7}{8} = \frac{15}{16} \cdot \frac{18}{5} - \frac{63}{8} = \frac{3}{16} \cdot 18 - \frac{63}{8} = \frac{54}{16} - \frac{63}{8} = \frac{54}{16} - \frac{63 \cdot 2}{8 \cdot 2} = \frac{54}{16} - \frac{126}{16} = \frac{54-126}{16} = \frac{-72}{16} = -4\frac{8}{16} = -4\frac{1}{2}\]
5) \[(\frac{5}{9} - \frac{3}{7}) : \frac{16}{63} = (\frac{5 \cdot 7}{9 \cdot 7} - \frac{3 \cdot 9}{7 \cdot 9}) : \frac{16}{63} = (\frac{35}{63} - \frac{27}{63}) : \frac{16}{63} = \frac{8}{63} : \frac{16}{63} = \frac{8}{63} \cdot \frac{63}{16} = \frac{8}{16} = \frac{1}{2}\]
6) \[\frac{4.7 + 3.54}{0.8} = \frac{8.24}{0.8} = 10.3\]
7) \[\frac{3.6 - 7}{0.08} = \frac{-3.4}{0.08} = -42.5\]
8) \[\frac{2.48 - 5}{2.4} = \frac{-2.52}{2.4} = -1.05\]
9) \[0.9 - 3.09 : 1.5 = 0.9 - 2.06 = -1.16\]
10) \[\frac{2.48 - 5}{2.4} = \frac{-2.52}{2.4} = -1.05\]
Ответ: 1) 2 19/28; 2) 42; 3) -2 10/27; 4) -4 1/2; 5) 1/2; 6) 10.3; 7) -42.5; 8) -1.05; 9) -1.16; 10) -1.05
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