Решение:
а) $$14 \frac{9}{73} - 1 \frac{5}{73} + 12 \frac{11}{73} = 13 \frac{4}{73} + 12 \frac{11}{73} = 25 \frac{15}{73}$$
б) $$17 \frac{4}{25} - 3 \frac{13}{25} - 1 \frac{2}{25} = 14 \frac{4}{25} - 3 \frac{13}{25} - 1 \frac{2}{25} = 13 \frac{29}{25} - 3 \frac{13}{25} - 1 \frac{2}{25} = 10 \frac{16}{25} - 1 \frac{2}{25} = 9 \frac{14}{25}$$
в) $$17 \frac{15}{40} + 3 \frac{9}{40} - 1 \frac{12}{40} = 20 \frac{24}{40} - 1 \frac{12}{40} = 19 \frac{12}{40} = 19 \frac{3}{10}$$
г) $$13 \frac{15}{48} - 1 \frac{19}{48} = 12 \frac{63}{48} - 1 \frac{19}{48} = 11 \frac{44}{48} = 11 \frac{11}{12}$$
Ответ: а) $$25 \frac{15}{73}$$, б) $$9 \frac{14}{25}$$, в) $$19 \frac{3}{10}$$, г) $$11 \frac{11}{12}$$