Е: 1) $\frac{1}{(a+b)^2}+\frac{1}{a+b}=$; 2) $\frac{1}{a-b}+\frac{1}{(a-b)^2}=$; 3) $\frac{1}{x-y}-\frac{1}{(x-y)^2}=$; 4) $\frac{3}{(n-m)^2}+\frac{1}{n-m}=$; 5) $\frac{2}{x+y}-\frac{a}{(x+y)^2}=$; 6) $\frac{5}{2a+b}-\frac{x}{(2a+b)^2}=$; 7) $\frac{1}{(m-2n)^2}-\frac{1}{(m-2n)^3}=$; 8) $\frac{3}{2(x+y)}+\frac{b}{(x+y)^2}=$; 9) $\frac{x}{(a-b)^2}+\frac{2}{5(a-b)}=$; 10) $\frac{b}{(x-y)^3}+\frac{10}{3(x-y)^2}=$.

Question

Вопрос: $Фото задания: Е: 1) $\frac{1}{(a+b)^2}+\frac{1}{a+b}=$; 2) $\frac{1}{a-b}+\frac{1}{(a-b)^2}=$; 3) $\frac{1}{x-y}-\frac{1}{(x-y)^2}=$;…$ Фото задания

Е: 1) $\frac{1}{(a+b)^2}+\frac{1}{a+b}=$; 2) $\frac{1}{a-b}+\frac{1}{(a-b)^2}=$; 3) $\frac{1}{x-y}-\frac{1}{(x-y)^2}=$; 4) $\frac{3}{(n-m)^2}+\frac{1}{n-m}=$; 5) $\frac{2}{x+y}-\frac{a}{(x+y)^2}=$; 6) $\frac{5}{2a+b}-\frac{x}{(2a+b)^2}=$; 7) $\frac{1}{(m-2n)^2}-\frac{1}{(m-2n)^3}=$; 8) $\frac{3}{2(x+y)}+\frac{b}{(x+y)^2}=$; 9) $\frac{x}{(a-b)^2}+\frac{2}{5(a-b)}=$; 10) $\frac{b}{(x-y)^3}+\frac{10}{3(x-y)^2}=$.

Accepted Answer

Приводим к знаменателю $(a+b)^2$: $\frac{1}{(a+b)^2}+\frac{a+b}{(a+b)^2}=\frac{a+b+1}{(a+b)^2}$.
$\frac{a-b}{(a-b)^2}+\frac{1}{(a-b)^2}=\frac{a-b+1}{(a-b)^2}$.
$\frac{x-y}{(x-y)^2}-\frac{1}{(x-y)^2}=\frac{x-y-1}{(x-y)^2}$.
$\frac{3}{(n-m)^2}+\frac{n-m}{(n-m)^2}=\frac{n-m+3}{(n-m)^2}$.
$\frac{2(x+y)-a}{(x+y)^2}$.
$\frac{5(2a+b)-x}{(2a+b)^2}$.
$\frac{m-2n-1}{(m-2n)^3}$.
$\frac{3(x+y)+2b}{2(x+y)^2}$.
$\frac{5x+2(a-b)}{5(a-b)^2}$.
$\frac{3b+10(x-y)}{3(x-y)^3}$.

Ответ: