Е. А. Ширяева Выполни действие: 17+25= 24 36 7) 24+ 4.6 6.6 8) 330+120= 8+7= 9) 27+18 10) 2+1= 16 7 11) 45+115 = 12) 1+2= 13)+ = 75 14) 216+32 3 9 15) 12+410 8 16) 3+1= 1 17)+8= Математика (5– ПРАКТИКА №9

7) \[ \frac{17}{24} + \frac{25}{36} = \frac{17 \cdot 3}{24 \cdot 3} + \frac{25 \cdot 2}{36 \cdot 2} = \frac{51}{72} + \frac{50}{72} = \frac{51+50}{72} = \frac{101}{72} = 1 \frac{29}{72} \]

8) \[ 3 \frac{7}{30} + 1 \frac{9}{20} = 3 \frac{7 \cdot 2}{30 \cdot 2} + 1 \frac{9 \cdot 3}{20 \cdot 3} = 3 \frac{14}{60} + 1 \frac{27}{60} = (3+1) + \frac{14+27}{60} = 4 \frac{41}{60} \]

9) \[ \frac{8}{27} + \frac{7}{18} = \frac{8 \cdot 2}{27 \cdot 2} + \frac{7 \cdot 3}{18 \cdot 3} = \frac{16}{54} + \frac{21}{54} = \frac{16+21}{54} = \frac{37}{54} \]

10) \[ 2 \frac{2}{3} + 1 \frac{1}{2} = 2 \frac{2 \cdot 2}{3 \cdot 2} + 1 \frac{1 \cdot 3}{2 \cdot 3} = 2 \frac{4}{6} + 1 \frac{3}{6} = (2+1) + \frac{4+3}{6} = 3 \frac{7}{6} = 3 + 1 \frac{1}{6} = 4 \frac{1}{6} \]

11) \[ \frac{16}{45} + 1 \frac{7}{15} = \frac{16}{45} + 1 \frac{7 \cdot 3}{15 \cdot 3} = \frac{16}{45} + 1 \frac{21}{45} = 1 \frac{16+21}{45} = 1 \frac{37}{45} \]

12) \[ 1 \frac{3}{11} + 2 \frac{2}{3} = 1 \frac{3 \cdot 3}{11 \cdot 3} + 2 \frac{2 \cdot 11}{3 \cdot 11} = 1 \frac{9}{33} + 2 \frac{22}{33} = (1+2) + \frac{9+22}{33} = 3 \frac{31}{33} \]

13) \[ \frac{7}{8} + \frac{1}{3} = \frac{7 \cdot 3}{8 \cdot 3} + \frac{1 \cdot 8}{3 \cdot 8} = \frac{21}{24} + \frac{8}{24} = \frac{21+8}{24} = \frac{29}{24} = 1 \frac{5}{24} \]

14) \[ 2 \frac{7}{16} + \frac{5}{32} = 2 \frac{7 \cdot 2}{16 \cdot 2} + \frac{5}{32} = 2 \frac{14}{32} + \frac{5}{32} = 2 \frac{14+5}{32} = 2 \frac{19}{32} \]

15) \[ 1 \frac{3}{4} + 4 \frac{9}{10} = 1 \frac{3 \cdot 5}{4 \cdot 5} + 4 \frac{9 \cdot 2}{10 \cdot 2} = 1 \frac{15}{20} + 4 \frac{18}{20} = (1+4) + \frac{15+18}{20} = 5 \frac{33}{20} = 5 + 1 \frac{13}{20} = 6 \frac{13}{20} \]

16) \[ 3 \frac{4}{7} + 1 \frac{8}{11} = 3 \frac{4 \cdot 11}{7 \cdot 11} + 1 \frac{8 \cdot 7}{11 \cdot 7} = 3 \frac{44}{77} + 1 \frac{56}{77} = (3+1) + \frac{44+56}{77} = 4 \frac{100}{77} = 4 + 1 \frac{23}{77} = 5 \frac{23}{77} \]

17) \[ \frac{7}{9} + 8 \frac{13}{27} = \frac{7 \cdot 3}{9 \cdot 3} + 8 \frac{13}{27} = \frac{21}{27} + 8 \frac{13}{27} = 8 \frac{21+13}{27} = 8 \frac{34}{27} = 8 + 1 \frac{7}{27} = 9 \frac{7}{27} \]