Решение:
Заполним пропуски, решая примеры на деление:
- \( 3 \div 3 = 1 \)
- \( 3 \div 3 = 1 \)
- \( 3 \div 3 = 1 \)
- \( 3 \div 3 = 1 \)
- \( 3 \div 3 = 1 \)
- \( 3 \div 3 = 1 \)
- \( 3 \div 3 = 1 \)
- \( 3 \div 3 = 1 \)
- \( 3 \div 3 = 1 \)
- \( 3 \div 3 = 1 \)
- \( 3 \div 3 = 1 \)
- \( 3 \div 3 = 1 \)
- \( 3 \div 3 = 1 \)
- \( 3 \div 3 = 1 \)
- \( 3 \div 3 = 1 \)
- \( 3 \div 3 = 1 \)
- \( 3 \div 3 = 1 \)
- \( 3 \div 3 = 1 \)
- \( 4 \div 2 = 2 \)
- \( 7 \div 1 = 7 \)
- \( 12 \div 3 = 4 \)
- \( 10 \div 2 = 5 \)
- \( 15 \div 3 = 5 \)
- \( 5 \div 1 = 5 \)
- \( 0 \div 5 = 0 \)
- \( 2 \div 1 = 2 \)
- \( 27 \div 3 = 9 \)
- \( 3 \div 1 = 3 \)
- \( 3 \div 1 = 3 \)
- \( 15 \div 5 = 3 \)
- \( 6 \div 2 = 3 \)
- \( 8 \div 4 = 2 \)
- \( 9 \div 3 = 3 \)
- \( 9 \div 1 = 9 \)
- \( 15 \div 3 = 5 \)
- \( 27 \div 3 = 9 \)
- \( 8 \div 1 = 8 \)
- \( 21 \div 3 = 7 \)
- \( 10 \div 2 = 5 \)
- \( 6 \div 2 = 3 \)
- \( 18 \div 2 = 9 \)
- \( 3 \div 1 = 3 \)
- \( 3 \div 3 = 1 \)
Ответ: 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 2, 7, 4, 5, 5, 5, 0, 2, 9, 3, 3, 3, 3, 2, 3, 9, 5, 9, 8, 7, 5, 3, 9, 3, 1.