Fill in the missing numbers in the addition problem.

Understanding the Problem:

This is a vertical addition problem where we need to find the missing digits in the addends and the sum. We can use our knowledge of addition and place value to solve it.

Step-by-Step Solution:

• Focus on the ones place: We see that a number plus 5 equals 2. Since we can't have a sum of 2 in the ones place when one of the addends is 5 (as it would be 5 or more), this means there must have been a carry-over from the ones place to the tens place. Therefore, the ones digit of the sum must be 12. So, the missing digit in the first addend must be 7 (because 7 + 5 = 12). We write down 2 in the ones place of the sum and carry over 1 to the tens place.
• Focus on the tens place: Now we have the carried-over 1 plus the digit 4 in the tens place of the first addend, plus the digit 3 in the tens place of the second addend. This sum should equal the tens digit of the final sum. So, 1 (carry-over) + 4 + 3 = 8. This means the missing digit in the tens place of the first addend should be 4, and the missing digit in the tens place of the second addend should be 3. The sum in the tens place is 8.
• Focus on the hundreds place (or potential carry-over): We have the tens place summing to 8. If there were a carry-over from the tens place, it would appear in the hundreds place of the sum. However, based on the problem's structure, it appears to be a two-digit sum. Therefore, the missing digit in the hundreds place of the first addend is 0, and the missing digit in the hundreds place of the second addend is 0.

Reconstructing the Problem:

• The first number is 047 (or simply 47).
• The second number is 035 (or simply 35).
• The sum is 082 (or simply 82).

Let's check: 47 + 35 = 82.

Answer: The missing numbers are 4 in the tens place of the first number, and the sum is 82.