Решение:
- \( -y \cdot 4 = -120 \)
\( -4y = -120 \)
\( y = \frac{-120}{-4} \)
\( y = 30 \) - \( -0.2x = 22 \)
\( x = \frac{22}{-0.2} \)
\( x = -110 \) - \( 2 \cdot (-t) = -28 \)
\( -2t = -28 \)
\( t = \frac{-28}{-2} \)
\( t = 14 \) - \( \frac{1}{7}y = -8 \)
\( y = -8 \cdot 7 \)
\( y = -56 \) - \( \frac{2}{7}x = -\frac{10}{21} \)
\( x = -\frac{10}{21} \cdot \frac{7}{2} \)
\( x = -\frac{10}{2} \cdot \frac{1}{3} \)
\( x = -5 \cdot \frac{1}{3} \)
\( x = -\frac{5}{3} \) - \( -\frac{4}{9}x = \frac{16}{17} \)
\( x = \frac{16}{17} \cdot \left(-\frac{9}{4}\right) \)
\( x = \frac{4}{17} \cdot \left(-\frac{9}{1}\right) \)
\( x = -\frac{36}{17} \)
Ответ: y = 30; x = -110; t = 14; y = -56; x = -\(\frac{5}{3}\); x = -\(\frac{36}{17}\)