Вопрос:

Find the solution to the following systems of equations: a) { x - 6y = 17, 5x + 6y = 13; б) { 4x - 7y = -12, -4x + 3y = 12; в) { 3x + 2y = 5, -5x + 2y = 45; г) { 9x - 4y = -13, 9x - 2y = -20.

Смотреть решения всех заданий с листа

Ответ:

The task is to solve four systems of linear equations. We will solve each system separately.

Brief explanation: For systems of linear equations, we can use methods such as substitution, elimination, or matrix methods. In this case, the elimination method seems most efficient for most of the systems due to the presence of coefficients that are opposites or easily made opposites.

System a)

The system of equations is:

  • $$x - 6y = 17$$
  • $$5x + 6y = 13$$

Step 1: Add the two equations together to eliminate y.

$$(x - 6y) + (5x + 6y) = 17 + 13$$

$$6x = 30$$

Step 2: Solve for x.

$$x = \frac{30}{6} = 5$$

Step 3: Substitute the value of x into the first equation to solve for y.

$$5 - 6y = 17$$

$$-6y = 17 - 5$$

$$-6y = 12$$

$$y = \frac{12}{-6} = -2$$

Solution for a): $$x = 5, y = -2$$

System б)

The system of equations is:

  • $$4x - 7y = -12$$
  • $$-4x + 3y = 12$$

Step 1: Add the two equations together to eliminate x.

$$(4x - 7y) + (-4x + 3y) = -12 + 12$$

$$-4y = 0$$

Step 2: Solve for y.

$$y = \frac{0}{-4} = 0$$

Step 3: Substitute the value of y into the first equation to solve for x.

$$4x - 7(0) = -12$$

$$4x = -12$$

$$x = \frac{-12}{4} = -3$$

Solution for б): $$x = -3, y = 0$$

System в)

The system of equations is:

  • $$3x + 2y = 5$$
  • $$-5x + 2y = 45$$

Step 1: Subtract the second equation from the first equation to eliminate y.

$$(3x + 2y) - (-5x + 2y) = 5 - 45$$

$$3x + 2y + 5x - 2y = -40$$

$$8x = -40$$

Step 2: Solve for x.

$$x = \frac{-40}{8} = -5$$

Step 3: Substitute the value of x into the first equation to solve for y.

$$3(-5) + 2y = 5$$

$$-15 + 2y = 5$$

$$2y = 5 + 15$$

$$2y = 20$$

$$y = \frac{20}{2} = 10$$

Solution for в): $$x = -5, y = 10$$

System г)

The system of equations is:

  • $$9x - 4y = -13$$
  • $$9x - 2y = -20$$

Step 1: Subtract the second equation from the first equation to eliminate x.

$$(9x - 4y) - (9x - 2y) = -13 - (-20)$$

$$9x - 4y - 9x + 2y = -13 + 20$$

$$-2y = 7$$

Step 2: Solve for y.

$$y = \frac{7}{-2} = -3.5$$

Step 3: Substitute the value of y into the first equation to solve for x.

$$9x - 4(-3.5) = -13$$

$$9x + 14 = -13$$

$$9x = -13 - 14$$

$$9x = -27$$

$$x = \frac{-27}{9} = -3$$

Solution for г): $$x = -3, y = -3.5$$

Final Answer:

  • a) $$x = 5, y = -2$$
  • б) $$x = -3, y = 0$$
  • в) $$x = -5, y = 10$$
  • г) $$x = -3, y = -3.5$$
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