The system of equations is:
Step 1: Add the two equations together to eliminate y.
$$(x - 6y) + (5x + 6y) = 17 + 13$$
$$6x = 30$$
Step 2: Solve for x.
$$x = \frac{30}{6} = 5$$
Step 3: Substitute the value of x into the first equation to solve for y.
$$5 - 6y = 17$$
$$-6y = 17 - 5$$
$$-6y = 12$$
$$y = \frac{12}{-6} = -2$$
Solution for a): $$x = 5, y = -2$$
The system of equations is:
Step 1: Add the two equations together to eliminate x.
$$(4x - 7y) + (-4x + 3y) = -12 + 12$$
$$-4y = 0$$
Step 2: Solve for y.
$$y = \frac{0}{-4} = 0$$
Step 3: Substitute the value of y into the first equation to solve for x.
$$4x - 7(0) = -12$$
$$4x = -12$$
$$x = \frac{-12}{4} = -3$$
Solution for б): $$x = -3, y = 0$$
The system of equations is:
Step 1: Subtract the second equation from the first equation to eliminate y.
$$(3x + 2y) - (-5x + 2y) = 5 - 45$$
$$3x + 2y + 5x - 2y = -40$$
$$8x = -40$$
Step 2: Solve for x.
$$x = \frac{-40}{8} = -5$$
Step 3: Substitute the value of x into the first equation to solve for y.
$$3(-5) + 2y = 5$$
$$-15 + 2y = 5$$
$$2y = 5 + 15$$
$$2y = 20$$
$$y = \frac{20}{2} = 10$$
Solution for в): $$x = -5, y = 10$$
The system of equations is:
Step 1: Subtract the second equation from the first equation to eliminate x.
$$(9x - 4y) - (9x - 2y) = -13 - (-20)$$
$$9x - 4y - 9x + 2y = -13 + 20$$
$$-2y = 7$$
Step 2: Solve for y.
$$y = \frac{7}{-2} = -3.5$$
Step 3: Substitute the value of y into the first equation to solve for x.
$$9x - 4(-3.5) = -13$$
$$9x + 14 = -13$$
$$9x = -13 - 14$$
$$9x = -27$$
$$x = \frac{-27}{9} = -3$$
Solution for г): $$x = -3, y = -3.5$$
Final Answer: